How do you remove .0 from the end of a number?

Question

When I get the output for print(f"{usernum} divided by {dividenum} is {usernum / dividenum}.") it will be something like 3.0 rather than 3

How would I remove the .0 from the end.

I'm very new at python.

This has already been answered. Check the link here. https://stackoverflow.com/questions/5807952/removing-trailing-zeros-in-python — VeryBhatti, Mar 12 '20 at 07:20
Does this answer your question? [Removing Trailing Zeros in Python](https://stackoverflow.com/questions/5807952/removing-trailing-zeros-in-python) — Romeo Sierra, Mar 12 '20 at 07:21

Sam Morgan · Accepted Answer · 2020-03-12T16:26:35.200

1

print(f"{usernum} divided by {dividenum} is {usernum / dividenum:.0f}.")

The :.0f format string syntax is using the fixed-point precision format specifier to round to 0 decimal places. This is functionally the same as using the built-in round function on the resulting float with precision None.

Other ways of achieving this

# Rounds to nearest whole number
print(f"{usernum / dividenum:.0f}")
print(f"{usernum / dividenum:.0g}")
print(f"{round(usernum / dividenum)}")
print(f"{int(usernum / dividenum)}")

# Convert to string and parse, doesn't round
print(f"{str(usernum / dividenum)[0]}")  # Inaccurate after 9
print(f"{str(usernum / dividenum).split('.')[0]}")

The approach needed will depend on your desired output precision.

edited Mar 12 '20 at 16:26

answered Mar 12 '20 at 07:20

Sam Morgan

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Add text describing this option. Are there others? – Frank C. Mar 12 '20 at 07:57
Good call! I was up far too late. Added explanation and other examples. – Sam Morgan Mar 12 '20 at 16:27

How do you remove .0 from the end of a number?

1 Answers1