Cut out letters using bash

Question

I want to cut out extra words without losing the ranges that follow emxaple :

int.domain.com<BR>stage.domain.com<BR>helth.domain.com

I want to remove it <BR>

Without losing it The two domains that follow

stage.domain.com
helth.domain.com

I want to do that by using the grep tool

And thanks

https://stackoverflow.com/a/1732454/836748 – Aaron D. Marasco Mar 17 '20 at 22:29 — Aaron D. Marasco, Mar 17 '20 at 22:29

score 1 · Accepted Answer · answered Mar 18 '20 at 03:43

1

Using sed

sed 's#<BR>#\n#g'

Demo:

:=>echo "int.domain.com<BR>stage.domain.com<BR>helth.domain.com"  | sed 's#<BR>#\n#g' 
int.domain.com
stage.domain.com
helth.domain.com
:=>

answered Mar 18 '20 at 03:43

Digvijay S

This answer is wrong, partially but still. Sed will not always substitute with `'\n'` - in cygwin/mingw for example, and more importantly how are you going to remove first domain from output as this was in a question? – tansy Mar 18 '20 at 10:03

score 0 · Answer 2 · answered Mar 17 '20 at 22:54

0

You can't use grep alone to do that. Grep only searches patterns not substitutes them.

$ echo "int.domain.com<BR>stage.domain.com<BR>helth.domain.com" | awk 'BEGIN{FS="<BR>"} { for (i=2; i<=NF; i++) print $i }'

stage.domain.com
helth.domain.com

FS is field separator, then print all from 2'nd element.

answered Mar 17 '20 at 22:54

tansy

Or just …`awk 1 RS='
|\n'`, RS is the record separator, so tell awk you have records separated by `
` or newlines – jthill Mar 18 '20 at 03:49
I tried that and it didn't work. Don't know where exactly is a catch here. It's not going to work as you wrote it - whole script must be in between `' '`. – tansy Mar 18 '20 at 10:11
mmm, I assumed GNU's awk, which handles regex record separators fine, I'd tested before commenting. – jthill Mar 18 '20 at 16:56

2 Answers2