Closing popup window by clicking close button in selenium

Question

I want to close the popup window that appears when I hit a particular url. Here is the "inspect element" window of that page:

Here is what I have tried:

driver.find_element_by_css_selector("i[@class='popupCloseIcon']").click()

But it gives following error:

InvalidSelectorException: Message: Given css selector expression "i[@class='popupCloseIcon']" is invalid: InvalidSelectorError: Document.querySelector: 'i[@class='popupCloseIcon']' is not a valid selector: "i[@class='popupCloseIcon']"

Here is the url where popup appears: https://www.investing.com/equities/oil---gas-dev-historical-data Once the url is opened through selenium, the pop up appears after a few seconds. How can I click that close button?

score 2 · Answer 1 · answered Mar 18 '20 at 11:54

The popup appears after some time, so you need wait to solve this. And you have invalid selector : i[@class='popupCloseIcon'], please use i[class*='largeBannerCloser']

Try the below:

driver.get('https://www.investing.com/equities/oil---gas-dev-historical-data')

try:
    popup = WebDriverWait(driver, 60).until(EC.visibility_of_element_located((By.CSS_SELECTOR, "i[class*='largeBannerCloser']")))
    popup.click()
except TimeoutException as to:
    print(to)

This is wait until 60 seconds maximum.

Following import:

from selenium.webdriver.common.by import By
from selenium.webdriver.support.ui import WebDriverWait
from selenium.webdriver.support import expected_conditions as EC
from selenium.common.exceptions import TimeoutException

The `*` in `i[class*='largeBannerCloser']` is not needed since `largeBannerCloser` is the full name of the class. A more CSS-like selector would be `i.largeBannerCloser`. — JeffC, Mar 22 '20 at 01:34

score 1 · Answer 2 · answered Mar 18 '20 at 14:20

As the pop up appears after a few seconds accessing the url https://www.investing.com/equities/oil---gas-dev-historical-data to to close the popup window you need to induce WebDriverWait for the element_to_be_clickable() and you can use either of the following Locator Strategies:

Using CSS_SELECTOR:

WebDriverWait(driver, 60).until(EC.element_to_be_clickable((By.CSS_SELECTOR, "i.popupCloseIcon.largeBannerCloser"))).click()

Using XPATH:

WebDriverWait(driver, 60).until(EC.element_to_be_clickable((By.XPATH, "//i[@class='popupCloseIcon largeBannerCloser']"))).click()

Note : You have to add the following imports :

from selenium.webdriver.support.ui import WebDriverWait
from selenium.webdriver.common.by import By
from selenium.webdriver.support import expected_conditions as EC

score 0 · Answer 3 · answered Mar 18 '20 at 11:16

First, "i[@class='popupCloseIcon']" is a invalid css selector locator, it should be "i[class='popupCloseIcon']". Second, there are four elements mapped to the "i[class='popupCloseIcon']", the css selector "div.right>i.popupCloseIcon" will help you to locate the target element

Closing popup window by clicking close button in selenium

3 Answers3