List to be sorted via lambda

Question

LIST = ['aaa', 'aa', 'ba', 'b', 'AA', 'zz', 'c']

print (sorted(LIST, key=lambda s: s.casefold())) 

print (sorted(LIST, key=lambda s: len(s))) 

combine both into one Lambda - expected result:

['b', 'c', 'aa', 'AA', 'ba',  'zz', 'aaa']

Answer 1

In your key parameter you can sort first by len, then if those are equal it will fall back to sort by str.casefold semantics.

>>> sorted(LIST, key=lambda s: (len(s), s.casefold()))
['b', 'c', 'aa', 'AA', 'ba', 'zz', 'aaa']