In Python, ignore digits in string but remove pure digits

Question

I am processing string like

This is python3 and learning it takes 100 hours

I want to remove only digits like 100 but want to keep digits when it is part of anything like python3.

I am trying the regex

text = re.sub('[0-9]', '', text)

but it is not working as expected. Help is appreciated.

You may now think about accepting an answer or comment one to get details ;) to reward those who spent time for you ;) — azro, Mar 20 '20 at 08:44

ruohola · Accepted Answer · 2020-03-20T14:25:01.773

1

You can just add a space to both sides of your regex, and then have a single space as the replacement. Remember to also a + to match one or more digits:

import re

text = 'This is python3 and learning it takes 100 hours'
text = re.sub(r' [0-9]+ ', ' ', text)
print(text)

Output:

This is python3 and learning it takes hours

edited Mar 20 '20 at 14:25

answered Mar 19 '20 at 12:37

ruohola

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score 0 · Answer 2 · answered Mar 19 '20 at 12:36

0

Try below,

text = re.sub(' [0-9]{1,} ', ' ', text)

answered Mar 19 '20 at 12:36

Gokul nath

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This will not capture digits from `100 hours learning required` – ManojK Mar 19 '20 at 12:39

azro · Answer 3 · 2020-03-19T12:41:01.823

0

You can use \b word boundary (class \d is for [0-9]) :

def clean(value):
    return re.sub(r"\b\d+\b", "", value)

if __name__ == "__main__":
    print(clean("This is python3 and learning it takes 100 hours"))  # This is python3 and learning it takes  hours

Regex demo

edited Mar 19 '20 at 12:41

answered Mar 19 '20 at 12:38

azro

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In Python, ignore digits in string but remove pure digits

3 Answers3