appending a list (i am not able to execute this code)

Question

def greet(x,y):
    z=[]
    z=x.append(y)
    return "Hi your ful name is : %s \n your firstname: %s \n lastname: %s" %(z.title(),x,y)

f_name=[]
l_name=[]

f_name=list(input("enter your firstname : ")) 
l_name=list(input("entere your lastname: "))

print(greet(f_name,l_name))

Is your goal just to print first name and last name in a string? — Shadab Hussain, Mar 20 '20 at 06:49
You want something like `z = f'{x} {y}'`; there's no need for any lists in this code. `f_name` and `l_name` should just be simple `str` values. — chepner, Mar 20 '20 at 13:26

Mehul Gupta · Answer 1 · 2020-03-20T13:17:52.317

-1

This happens because when we use x.append(y), the operation is performed on x and hence nothing is returned when we append() as it happens when we use sort() with a list.Hence z is None type object

edited Mar 20 '20 at 13:17

answered Mar 20 '20 at 12:59

Mehul Gupta

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`z` is *not* a list after the second assignment to `z`. – chepner Mar 20 '20 at 13:03
How?? both x & y are lists as both inputs are converted to lists as & when taken from the user. Hence z is also a list i guess!! – Mehul Gupta Mar 20 '20 at 13:07
`x.append(y)` does not return a list. – chepner Mar 20 '20 at 13:07
yupp!! just tested it. Thanks!! – Mehul Gupta Mar 20 '20 at 13:11

appending a list (i am not able to execute this code)

1 Answers1