Bad substitution when using bash

Asked Mar 20 '20 at 17:30

Active Mar 20 '20 at 17:38

Viewed 91 times

This is my code

#!/bin/bash

PING_STATUS="${netcat -vz mc.bella.wtf 25565}"
curl -H "Content-Type: application/json" -X POST -d '{"embeds": [{"title": "Server Status:","color": 16027903,"description": "'"$PING_STATUS"'"}]}' "$WEBHOOK"

I get this when running it

mc@ubuntu:~$ serverping
./server/server/ping: line 3: ${netcat -vz mc.bella.wtf 25565}: bad substitution

I already tried escaping the - and . to be sure

EDIT: solved

I had to use () instead of {}

edited Mar 20 '20 at 17:38

asked Mar 20 '20 at 17:30

5HT2

1

Did you mean `$(...)` instead of `${...}`? `${...}` is for variable substitution, `$(...)` is for running commands and substituting their output. – Thomas Mar 20 '20 at 17:32
That fixes the issue, but now when it's run the output is just nothing to bash? – 5HT2 Mar 20 '20 at 17:33
`netcat`'s verbose output (`-v`) goes to stderr, so you need to tack on `2>&1` to capture it. – Thomas Mar 20 '20 at 17:36
That worked, thank you! – 5HT2 Mar 20 '20 at 17:37

Bad substitution when using bash

0 Answers0