How to achieve the below output in python using loops and range functionality?

Question

How to achieve the below output in python with the help of range and loops functionality available in python?

  Expected output:
  0000
  1111
  2222
  3333

The below way works, but if the number needs to be printed till 100 then, 100 print statements needs to be written, the below way is a time consuming process.

Rather than writing in the below way of writing the code and achieving the output in the above way. Is there any short way to write the code and achieve the desired output?

  for i in range(4):
    print(i,end='')
    print(i,end='')
    print(i,end='')
    print(i)

I am not sure I understand your problem. If you need to print numbers until a 100, you just need to change the `4` to a `100` in the loop, no added `print`s are necessary. Did you mean that you want to print each number `100` times in a row??? — Tomerikoo, Mar 21 '20 at 20:36

kederrac · Answer 1 · 2020-03-21T20:34:33.037

2

you can use:

n = 4
for i in range(n):
    print(str(i)*n)

output:

or you can use:

print(*[e*4 for e in map(str, range(n))], sep='\n')

or:

print(*[str(e) * 4 for e in range(n)], sep='\n')

output:

for 100 prints you have to set n = 100

edited Mar 21 '20 at 20:34

answered Mar 21 '20 at 20:24

kederrac

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score 0 · Answer 2 · answered Mar 21 '20 at 20:26

0

If you're not sure about how many iterations, this will be executed this should work as well:

  n = int(input("Enter the number of iterations:"))
  for num in range(n):
     print(str(num)*4)

Output for n = 4:

answered Mar 21 '20 at 20:26

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How to achieve the below output in python using loops and range functionality?

2 Answers2