How to delete a dictionary in a list in python?

Question

I am just looking for help to delete a specific dictionary in a list with a specific stipulation without using the index number.

For example, how would I remove supplier with supplier_id=103 in the following

suppliers = [
{"contact_firstname": "Jason", 
 "supplier_id": 101},
{"contact_firstname": "Paul", 
 "supplier_id": 102},
{"contact_firstname": "Mark", 
 "supplier_id": 103}]

Get the index of the element you want to remove, then use `suppliers.pop(index)` — Barmar, Mar 23 '20 at 05:21
I'm trying to do it without knowing the index number. I understand you can use this but was looking a way to do it without — Jake Lazzari, Mar 23 '20 at 05:22
You can find the index number with a simple loop. See https://stackoverflow.com/questions/4391697/find-the-index-of-a-dict-within-a-list-by-matching-the-dicts-value — Barmar, Mar 23 '20 at 13:40

score 1 · Answer 1 · answered Mar 23 '20 at 05:22

1

You can write it like this:

supplier_list2 = [x for x in suppliers if x["supplier_id"] != 103]

It will remove all entries with supplier_id 103. If you want to exclude a list of ID's:

excluded = [102, 103]
supplier_list2 = [x for x in suppliers if x["supplier_id"] not in excluded]

answered Mar 23 '20 at 05:22

pissall

7,109
2
25
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I copied and pasted that directly and then proceeded to reprint the list and it came out exactly the same. Not sure what's wrong – Jake Lazzari Mar 23 '20 at 05:31
@JakeLazzari Did you print `suppliers` or `supplier_list2`? – Barmar Mar 23 '20 at 13:41

score 0 · Accepted Answer · answered Mar 23 '20 at 05:30

0

You can try this:

suppliers[:] = [d for d in suppliers if d.get('supplier_id') != 103]

answered Mar 23 '20 at 05:30

Siddhant Shrivastav

259
4
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Can you try to understand/explain why this answer worked and mine didn't? – pissall Mar 23 '20 at 05:33

How to delete a dictionary in a list in python?

2 Answers2