Access REST API via lua script

Question

Is there way to access rest api with pure lua script

GET / POST both way need to access and display response

i already tried

    local api = nil
    local function iniit()
    if api == nil then
      -- body
      api = require("http://api.com")
            .create()
            .on_get(function ()
                return {name = "Apple",
                        id = 12345}

            end)
        end
     end

What Lua library are you using? Where I can read the doc on `.on_get`? — Egor Skriptunoff, Mar 24 '20 at 12:07
@EgorSkriptunoff , i'm completely noob for lua, so dont know .on_get is a library or not. Anyone can help ? — C.V, Mar 24 '20 at 14:03
If the REST API is documented in OpenAPI/Swagger, you may want to try using OpenAPI Generator to generate the Lua API client instead: https://github.com/OpenAPITools/openapi-generator — William Cheng, Jul 05 '20 at 08:16
See [this answer](https://stackoverflow.com/a/65783685/52499). — x-yuri, Jan 18 '21 at 23:55

score 1 · Accepted Answer · answered Apr 06 '20 at 16:01

In linux , mac we can easily install luarocks , and then we can install curl package. It's easiest way to unix like os.


-- HTTP Get
local curl = require('curl')

curl.easy{
  url = 'api.xyz.net?a=data',
  httpheader = {
    "X-Test-Header1: Header-Data1",
    "X-Test-Header2: Header-Data2",
  },
  writefunction = io.stderr -- use io.stderr:write()
}
:perform()
:close()

In windows i faced several problems. Cant install luarocks correctly. then luarock install command not work correctl, etc..

In first dwnload lua from official site, and then create structure like (below web site)

http://fuchen.github.io/dev/2013/08/24/install-luarocks-on-windows/

then i download lua luadist http://luadist.org/

then i got same structure luadist extracted folder and lua folder.

merged luadist folder and lua folder Finaly we can use http.soket

local http=require("socket.http");

local request_body = [[login=user&password=123]]
local response_body = {}

local res, code, response_headers = http.request{
    url = "api.xyz.net?a=data",
    method = "GET", 
    headers = 
      {
          ["Content-Type"] = "application/x-www-form-urlencoded";
          ["Content-Length"] = #request_body;
      },
      source = ltn12.source.string(request_body),
      sink = ltn12.sink.table(response_body),
}

print(res)
print(code)

if type(response_headers) == "table" then
  for k, v in pairs(response_headers) do 
    print(k, v)
  end
end

print("Response body:")
if type(response_body) == "table" then
  print(table.concat(response_body))
else
  print("Not a table:", type(response_body))
end

IF YOU DO THESE STEPS CORRECTLY , THIS WILL BE WORK 1000% SURE

Access REST API via lua script

1 Answers1