a = ['*','#','$'] b = [1,4,7]
How can I make use of the above lists and loop to print the pattern with the required number of rows? Here are 2 examples if the input is 5 and 10 respectively. Do not need to print the bracket on each line. Thanks.
Number of rows: 5
(*)
(####)
($$$$$$$)
(*)
(####)
Number of rows: 10
(*)
(####)
($$$$$$$)
(*)
(####)
($$$$$$$)
(*)
(####)
($$$$$$$)
(*)
You can use the modulus operator (%) to iterate through a and b and repeat from the beginning of the list.
a = ['*', '#', '$']
b = [1, 4, 7]
rows = int(input('>>> '))
print('\n\n'.join(f'({a[i % len(a)] * b[i % len(b)]})' for i in range(rows)))
You can multiply A* B and then shift A and B by 1 per Loop Iteration
Easy to implement user input
a = ['*','#','$']
b=[1,4,7]
b.reverse()
b = b[-1:] + b[:-1]
print(b)
for x in range(5):
print(a[0]*b[0])
a = a[-1:] + a[:-1]
b = b[-1:] + b[:-1]
