python remove brackets if followed by words

Asked Mar 28 '20 at 22:19

Active Mar 28 '20 at 22:30

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I am trying to remove brackets [] if there are words in them. For example in the sentence below, I am trying to remove the [] around result. I tried \[[A-Za-z] which can pick up the open bracket [, but I couldn't figure out how to detect the close bracket ] and how to delete them. Could someone please help? Many thanks.

This should be in the [result].

asked Mar 28 '20 at 22:19

user3735871

You need to escape the `]` with `\]` – rdas Mar 28 '20 at 22:20
1

`r = re.sub(r"\[([^]]+)\]", r"\1"", s)` - https://trinket.io/python3/9f0a3ca34d – Pedro Lobito Mar 28 '20 at 22:23
What's the desired result? – Paolo Mar 28 '20 at 22:24
@PedroLobito Thanks! this is what I'm looking for. Could you explain a bit more about your answer like `\1` and the use of ^ here? I thought ^ was for negate. If you move this to an answer I could accept it. – user3735871 Mar 28 '20 at 22:29
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@user3735871 https://regex101.com/r/MLHq1K/1 - Check the regex explanation on the right side. – Pedro Lobito Mar 28 '20 at 22:30

python remove brackets if followed by words

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