facing error while working with 'for' loop in python

Question

While doing a question of printing table I faced a problem which I wasn't able to understand...

please explain:

x=input('enter a number btw 1-12')
if(not x.isdigit() and x>13 and x<0):
    print("value should be btw 1 to 12")
else:
    y=range(1,11)
    for i in y:
        print(x*i)**

result-(when x=2)

I don't know why I am getting a series instead of

`x` is a string and needs converting to an `int` if you want to compare it to `13` or `0`. — Peter Wood, Mar 28 '20 at 22:27
`x` is a string, not an integer, so `x>13 and x<0` won't work. You may try `x=int(input('enter a number btw 1-12'))` — Pedro Lobito, Mar 28 '20 at 22:27
Does this answer your question? [How can I read inputs as numbers?](https://stackoverflow.com/questions/20449427/how-can-i-read-inputs-as-numbers) — B. Go, Mar 28 '20 at 22:45

score 1 · Accepted Answer · edited Mar 28 '20 at 22:29

1

The input function in Python always takes the input as a string.

You need to convert it to an integer using int() or float using float() before adding it.

Like this:

else:
    x = int(x)
    y=range(1,11)
    for i in y:
        print(x*i)**

edited Mar 28 '20 at 22:29

Pedro Lobito

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answered Mar 28 '20 at 22:28

Thaer A

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score 0 · Answer 2 · answered Mar 28 '20 at 22:31

You need to specify that you input is an int and not a string. Also I would use the 'or' operator instead of 'and' in the if(x>13 or x<0):. Hope that helps!

x=int(input('enter a number btw 1-12'))

if(x>13 or x<0):
    print("value should be btw 1 to 12")

else:
    y=range(1,11)
    for i in y:
        print(x*i)

facing error while working with 'for' loop in python

2 Answers2