Writing a shell script to loop and print out numbers 0-100 and if they are even or odd

Question

I'm trying to write a script to do as the question title says but I'm getting an error and I can not understand why. I'm quite new to bash and shell scripting so any help is appreciated. here is my code:

for i in {0..100}
do
if [ $i % 2 = 0  ]
        echo "Number: $i and is even."
else
        echo "Number: $i and is odd."
fi
done

Use https://shellcheck.net – Jetchisel Mar 31 '20 at 12:26 — Jetchisel, Mar 31 '20 at 12:26

score 0 · Accepted Answer · answered Mar 31 '20 at 12:19

0

You are missing a then after if. Also your test expression in if is incorrect

for i in {0..100}
do
if [ $(($i % 2)) -eq 0  ]
then
        echo "Number: $i and is even."
else
        echo "Number: $i and is odd."
fi
done

$(($i % 2)) is for Arithmetic-Expansion

answered Mar 31 '20 at 12:19

Ashwani

1,938
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15

This works thank you! I will mark as the answer when I can – burnie5749 Mar 31 '20 at 12:21

Writing a shell script to loop and print out numbers 0-100 and if they are even or odd

1 Answers1