Convert Time since Epoch to HEX or Byte Array

Question

How can I convert the time since epoch to Hex in Go?

It should look like this: 5E839BAB

EDIT: I was not able to find anything similar asked already. My Plan was to get the current time in Unix (Epoch) -> convert it to a Byte Array and then use hex.EncodeToString() to get it as hex

It's better to include the relevant information to the original question. If the obvious answer isn't what you want, add that. [ask] — JimB, Mar 31 '20 at 20:29

Burak Serdar · Accepted Answer · 2020-03-31T20:19:24.117

4

You can get the epoch of time value using t.Unix():

t:=time.Now()
fmt.Sprintf("%X",t.Unix())

To get this as a byte array:

import "encoding/binary"
...
out:=make([]byte,4)
binary.LittleEndian.PutUint32(out,uint32(t.Unix()))

Or, use BigEndian.

edited Mar 31 '20 at 20:19

answered Mar 31 '20 at 19:44

Burak Serdar

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Thanks, i knew that already though. I need this as a 4 byte long Byte Array though (see https://stackoverflow.com/questions/29273498/getting-date-time-in-unix-time-as-byte-array-which-size-is-4-bytes-with-java) – NecronomiconCoding Mar 31 '20 at 19:53
@NecronomiconCoding Added that to the answer. – Burak Serdar Mar 31 '20 at 19:59
Thank you, this solved my answer. Just replace int32 with uint32 :) – NecronomiconCoding Mar 31 '20 at 20:09

Convert Time since Epoch to HEX or Byte Array

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