Access to return value from Task (C#)

Question

I got method:

class C1
{
  private async Task OpenCar()    
 {
   ...
    await p.ReopenNewDoor(x, y);
    return //false or true
  }
}

Then:

class C1
{
  public Task ReopenNewDoor(int x, int y)
  {
     return mvvm.DoSomething(x,y)
  }      
}

And:

class C3
{
  internal async Task<bool> DoSomething(int x, int y)
  {
    .....
    if(a = b) return false;
    ....
    if(z!) return true;
  }
}

How can I know what will return ReopenNewDoor? (true or false)

Well, you don't have to return anything; `private async Task OpenCar() {... await p.ReopenNewDoor(x, y);}` — Dmitry Bychenko, Apr 03 '20 at 12:45
You should declare the return type ofr `ReopenNewDoor` as `Task` and use `Result` property, or simply `await` for it — ironstone13, Apr 03 '20 at 12:47

AlleXyS · Answer 1 · 2020-04-03T13:29:37.697

0

class C1
{
  private async Task<bool> OpenCar()    
  {
   ...
    var result = await p.ReopenNewDoor(x, y);
    return result;
  }
}

If this not working, you can access result of task using

p.ReopenNewDoor(x, y).Result;

edited Apr 03 '20 at 13:29

answered Apr 03 '20 at 12:42

AlleXyS

`result` is `bool` not `Task`. – Johnathan Barclay Apr 03 '20 at 12:49
really? then must update method header: private async Task OpenCar – AlleXyS Apr 03 '20 at 12:51
It should be `private async Task OpenCar()` – Johnathan Barclay Apr 03 '20 at 12:52
yes. but the body is the same. Can read result of task using Result then – AlleXyS Apr 03 '20 at 12:54
1

There's no need to access `.Result` because `await` unwraps the result for you. `await p.ReopenNewDoor(x, y).Result;` will not compile either, because `Result` is `bool`, so you are trying to `await` a `bool`. – Johnathan Barclay Apr 03 '20 at 13:23

1 Answers1