How can gather all the results of several findById searches in a single array?

Asked Apr 04 '20 at 16:47

Active Apr 04 '20 at 18:15

Viewed 61 times

Consider the code:

const id=aux[0].healthyTissue[0];
const aux4 = await Hidden.findById(id).populate(
    "children"
);

As you may have noticed, aux is an array and so is aux[i].healthyTissue[0].

Problem: I want to gather all the information in a single array called aux4, as I am doing for index equal 0, I want an automatic way to search inside all the arrays.

I have tried something like ForEach and map, with no success, I cannot make it wait for the result, it keeps coming empty on the following res.json I thought about pipe, however, I could make it work on this case.

Obs. the code showed works, but I want to go through all the elements, gather them in a single array, and return in a res.json

edited Apr 04 '20 at 16:50

asked Apr 04 '20 at 16:47

Jorge Guerra Pires

[`forEach` does not work with `await`](https://stackoverflow.com/q/37576685/1048572). – Bergi Apr 04 '20 at 16:50
Just don't use `findById`, but a mongoose function that can query multiple elements by a condition? – Bergi Apr 04 '20 at 16:50
you mean `find()` instead? – Jorge Guerra Pires Apr 04 '20 at 16:51
I don't know mongodb in detail, but there should be something like `hidden.find({id: {"$in":arr }})` – Bergi Apr 04 '20 at 16:53
No sucess, I have tried `for`, the same problem! It does not wait for the result. – Jorge Guerra Pires Apr 04 '20 at 17:12
Please post that code you tried. – Bergi Apr 04 '20 at 18:14
I have decided to follow another strategy, different from this one. Thanks for the attention. – Jorge Guerra Pires Apr 04 '20 at 18:39

How can gather all the results of several findById searches in a single array?

0 Answers0