Check if the random number exists in the array

Question

How can I check if a number exists in an array using if statement? I'm trying to print "found" if it exists and "not found" otherwise. Here is my code:

for(int i = 0; i < arr5.length; i++) 

    arr5[i] = (int)(Math.random()*100000 + 0);

Scanner input = new Scanner(System.in);
// here i will input my search random number
System.out.print("Input search key: ");
int searchKey = input.nextInt();

Does this answer your question? [Java, Simplified check if int array contains int](https://stackoverflow.com/questions/12020361/java-simplified-check-if-int-array-contains-int) — Doi9t, Apr 05 '20 at 01:38

score 0 · Answer 1 · answered Apr 05 '20 at 01:35

Use an IntStream of the array values and check if any of them match the value provided by the Scanner.

arr5[i] = (int)(Math.random()*100000 + 0);


Scanner input = new Scanner(System.in);
    here i will input my search random number
System.out.print("Input search key: ");
int searchKey = input.nextInt();

if (IntStream.of(arr5).anyMatch(val -> val == searchKey)) {
   // found
}

score 0 · Answer 2 · answered Apr 05 '20 at 03:16

0

you can do this by a for each loop.

for ( int number: arr5 ) {
if ( number == searchKey ) {
// do everything you want
System.out.println("my key is in the array");
break;
}
}

answered Apr 05 '20 at 03:16

hamidreza75

567
6
15

Check if the random number exists in the array

2 Answers2