-6

I would like to be able to insert a line of code that counts the number of times the output is "watch".

This is the picture of my current code

Barmar
  • 741,623
  • 53
  • 500
  • 612
a_magnani
  • 3
  • 3
  • 7
    Please post code as text. It makes it easier for people to help you by being able to copy-paste it. Also it seems you are aware of variables. Did you know you can do something like `x = x + 1`? If you start with `x = 0` you can count stuff – Tomerikoo Apr 05 '20 at 21:29
  • add a count variable and increment whenever the condition is watch and finally print it – coldy Apr 05 '20 at 21:31
  • You can calculate it arithmetically, there's no need to count. – Barmar Apr 05 '20 at 21:32
  • A simple counter maybe? Something like `i += 1` – JvdV Apr 05 '20 at 21:33

2 Answers2

1

Try this one:

counter = 0
while Amzn > 1000:
    counter+=1
    print("Watch")
    Amzn = Amzn - (Amzn*.0103)
else:
    print("buy")
print(counter)
Gabio
  • 9,126
  • 3
  • 12
  • 32
0
i = 0

[...stuff...]

i += 1
print(f"Watch {i}")
Lydia van Dyke
  • 2,466
  • 3
  • 13
  • 25
  • It would be clearer for the OP (who seems to be a beginner) to show the actual `while` loop than `...stuff...`. – Gino Mempin Apr 05 '20 at 23:59