I have 3 lists and one string like this:
a = ['a', 'b', 'c']
b = [1, 2, 3, 4, 5]
c = [10, 11, 14, 15, 16]
string = 'buy'
I need a list of dictionaries like this:
[{'a':1 , 'b':10 , 'c':'buy'},{'a':2 , 'b':11 , 'c':'buy'},{'a':3 , 'b':14 , 'c':'buy'},...]
You can just zip b and c and use it to make the dictionaries in a comprehension:
a = ['a', 'b', 'c']
b = [1, 2, 3, 4, 5]
c = [10, 11, 14, 15, 16]
[{'a':a, 'b':b, 'c':'buy'} for a, b, in zip(b,c)]
Result:
[{'a': 1, 'b': 10, 'c': 'buy'},
{'a': 2, 'b': 11, 'c': 'buy'},
{'a': 3, 'b': 14, 'c': 'buy'},
{'a': 4, 'b': 15, 'c': 'buy'},
{'a': 5, 'b': 16, 'c': 'buy'}]
If you want to include the keys from a dynamically, you can zip them in too with something like itertools zip_longest to grab the static string:
from itertools import zip_longest
a = ['a', 'b', 'c']
b = [1, 2, 3, 4, 5]
c = [10, 11, 14, 15, 16]
[dict(zip_longest(a, tup, fillvalue='buy')) for tup in zip(b,c)]
Same result:
[{'a': 1, 'b': 10, 'c': 'buy'},
{'a': 2, 'b': 11, 'c': 'buy'},
{'a': 3, 'b': 14, 'c': 'buy'},
{'a': 4, 'b': 15, 'c': 'buy'},
{'a': 5, 'b': 16, 'c': 'buy'}]
Yet another way is to use itertools.repeat() to include the static string in the zipped tuple:
from itertools import repeat
a = ['a', 'b', 'c']
b = [1, 2, 3, 4, 5]
c = [10, 11, 14, 15, 16]
[dict(zip(a, tup)) for tup in zip(b,c, repeat('buy'))]
This should do what you're looking for:
[{a[0]:vb, a[1]:vc, a[2]:string} for vb, vc in zip(b, c)]
It produces:
[{'a': 1, 'b': 10, 'c': 'buy'},
{'a': 2, 'b': 11, 'c': 'buy'},
{'a': 3, 'b': 14, 'c': 'buy'},
{'a': 4, 'b': 15, 'c': 'buy'},
{'a': 5, 'b': 16, 'c': 'buy'}]
It takes the dict keys from list a, and 'buy' comes from string.
You can use zip(), list comprehension and dictionary comprehension for your task
Try this:
a = ['a', 'b', 'c']
b = [1, 2, 3, 4, 5]
c = [10, 11, 14, 15, 16]
print([{ a[0]:i, a[1]:j, a[2]:'buy'} for i,j in zip(b,c)])
OR
print([dict(zip(a, [i, j, "buy"])) for i,j in zip(b,c)])
Outputs:
[{'a': 1, 'b': 10, 'c': 'buy'}, {'a': 2, 'b': 11, 'c': 'buy'}, {'a': 3, 'b': 14, 'c': 'buy'}, {'a': 4, 'b': 15, 'c': 'buy'}, {'a': 5, 'b': 16, 'c': 'buy'}]
