Python: How do i Remove a CERTAIN amount of decimal in a float

Question

so i had this problem where i generated numbers from 0-1 with a step of 0.01 but the numbers have so many decimals like 0.010101010101.I only need it in the form 0.01 with two decimals.

How do i remove the rest of decimals ?

How exactly are you generating these numbers? What you observe can't be explained by the round-off error implicit in floats. You seem to be doing some sort of weird string concatenation. Either that or this in another duplicate of [is floating point math broken?](https://stackoverflow.com/q/588004/4996248) — John Coleman, Apr 09 '20 at 14:02

score 0 · Answer 1 · answered Apr 09 '20 at 14:04

0

You can format the decimal like

your_value = 0.1010101010
desired_value = '%.2f' % your_value

Now desired_value will have the decimal upto 2 places.

answered Apr 09 '20 at 14:04

dxillar

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score 0 · Answer 2 · answered Apr 09 '20 at 14:05

0

Or you could use decimal. Look at the documentation in the link: https://docs.python.org/3/library/decimal.html

answered Apr 09 '20 at 14:05

LUIGI SAVINO

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score 0 · Answer 3 · answered Apr 09 '20 at 14:06

0

Round num to digits places. round(num, digits)

answered Apr 09 '20 at 14:06

David Smolinski

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This worked the best .Thank you – Enes Semih YARALI Apr 09 '20 at 14:09

Python: How do i Remove a CERTAIN amount of decimal in a float

3 Answers3