Removing specific character from the end of strings in list in python

Question

Let's say I have a list that is something like this:

lst = ['Joe C', 'Jill', 'Chad', 'Cassie C']

I want to remove the last character from each string if that character is a 'C'. At the moment I'm stuck at this impass:

no_c_list = [i[:-1] for i in lst if i[-1:] == 'C']

However, this would return a list of:

['Joe', 'Cassie']

Does this answer your question? [if else in a list comprehension](https://stackoverflow.com/questions/4406389/if-else-in-a-list-comprehension) — AMC, Apr 11 '20 at 00:17

Dani Mesejo · Accepted Answer · 2020-04-11T00:15:25.393

2

lst = ['Joe C', 'Jill', 'Chad', 'Cassie C']

result = [e.rstrip('C') for e in lst]

print(result)

Output

['Joe ', 'Jill', 'Chad', 'Cassie ']

From the documentation:

Return a copy of the string with trailing characters removed. The chars argument is a string specifying the set of characters to be removed.

Also, as mentioned by @dawg:

result = [e.rstrip(' C') for e in lst]

If you want to remove the trailing whitespace also.

edited Apr 11 '20 at 00:15

answered Apr 11 '20 at 00:13

Dani Mesejo

1

Or `[e.rstrip(' C') for e in lst]` if you don't want the trailing space... – dawg Apr 11 '20 at 00:15
1

Note that this will incorrectly remove `'CC'` from `'Joe CC'`. – blhsing Apr 11 '20 at 04:44

score 1 · Answer 2 · answered Apr 11 '20 at 00:09

1

Try this:

lst = ['Joe C', 'Jill', 'Chad', 'Cassie C']

new_list = [ i[:-2] if i[-2:] == " C" else i for i in lst ]
print(new_list)

answered Apr 11 '20 at 00:09

AmirHmZ

score 0 · Answer 3 · answered Apr 11 '20 at 00:13

0

You could use a regex:

>>> lst = ['Joe C', 'Jill', 'Chad', 'Cassie C']
>>> import re
>>> [re.sub(r' C$', '', s) for s in lst]
['Joe', 'Jill', 'Chad', 'Cassie']

answered Apr 11 '20 at 00:13

dawg

3 Answers3