Why parseFloat() in js rounding the number if the value is above 14 digit in real part

Question

For example,
var a = parseFloat("123456789012345678.778") gives the output as 123456789012345680

This is Interesting also for me. Maybe this thread might help: https://stackoverflow.com/questions/1458633/how-to-deal-with-floating-point-number-precision-in-javascript — Harun Yilmaz, Apr 13 '20 at 10:33

score 0 · Answer 1 · answered Apr 13 '20 at 10:34

0

parseFloat converts BigInt syntax to Numbers, losing precision. This happens because the trailing n character is discarded.

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answered Apr 13 '20 at 10:34

Abhishek Jain

1 Answers1