Scan 10 numbers, store them in an array and then reverse the array

Question

I'm supposed to write a program in java that scans 10 double numbers and then stores them in an array. The numbers are then supposed to be reversed and printed. This is what I've written. The program prints the array in the right order instead of reversed, how can i fix it?

public class ReverseNumbers {

    public static void main(String[] args) {
        Scanner scan = new Scanner(System.in);
        // Fyll i egen kod

        double[] a = new double[10];


        for(int i = a.length - 1; i >=0; i--){
              a[i] = scan.nextDouble();

            System.out.print(" " + a[i]);
        }
    }
}

It seems to be duplicating [Java Array Sort descending?](https://stackoverflow.com/questions/1694751/java-array-sort-descending) — Nowhere Man, Apr 15 '20 at 11:17
@AlexRudenko - No, OP does not want to sort the array. He/she just wants to print it in reverse order of entry. — Arvind Kumar Avinash, Apr 15 '20 at 11:46

score 1 · Accepted Answer · edited Apr 25 '20 at 12:07

You need to use Arrays.toString or another loop to print the array.

import java.util.Arrays;
import java.util.Scanner;

public class Main {
    public static void main(String[] args) {
        Scanner scan = new Scanner(System.in);
        double[] a = new double[10];
        System.out.println("Enter " + a.length + " numbers: ");
        for (int i = a.length - 1; i >= 0; i--) {
            a[i] = scan.nextDouble();
        }

        // Either print it like this
        System.out.println(Arrays.toString(a));

        // Or like this
        for (double d : a) {
            System.out.print(d + " ");
        }

        System.out.println();

        // Or like this
        for (int i = 0; i < a.length; i++) {
            System.out.print(a[i] + " ");
        }
    }
}

A sample run:

Enter 10 numbers: 
10 20 30 5 15 25 12 22 32 42
[42.0, 32.0, 22.0, 12.0, 25.0, 15.0, 5.0, 30.0, 20.0, 10.0]
42.0 32.0 22.0 12.0 25.0 15.0 5.0 30.0 20.0 10.0 
42.0 32.0 22.0 12.0 25.0 15.0 5.0 30.0 20.0 10.0

score 0 · Answer 2 · edited Apr 15 '20 at 11:57

This line of code worked :), thanks guys!

public class ReverseNumbers {

    public static void main(String[] args) {
        Scanner scan = new Scanner(System.in);
        // Fyll i egen kod

        double[] a = new double[10];


        for(int i=0; i<10; i++){
            a[i] = scan.nextDouble();
        }

        for(int i = a.length - 1; i >=0; i--){


            System.out.print(a[i] + " ");
        }
    }
}

score -1 · Answer 3 · edited Apr 15 '20 at 11:58

-1

See as a beginner I don't know Java language, but I can solve your question using Qbasic easily.

CLS
N = 1
DO
    INPUT "ENTER THE NUMBER"; A(N)
    N = N + 1
LOOP WHILE N <= 10
CLS
DO
    PRINT A(N)
    N = N - 1
LOOP WHILE N > 0
END

edited Apr 15 '20 at 11:58

halfer

19,824
17
99
186

answered Apr 15 '20 at 11:36

Rahul_29

1
3

2

Please do not answer questions in another language, unless the stated question asks about solutions in the language you are wanting to answer in. – halfer Apr 15 '20 at 11:58

Scan 10 numbers, store them in an array and then reverse the array

3 Answers3