Replace multiple chars in one run

Question

I want to have a program like the one below:

a = xy
b = a.replace("x", "y")
c = b.replace("y", "x")
print(c)

And I want the output to be "yx" but because the program is running the same string again the output is looking like "xx".

I hope you're getting my point.

Does this answer your question? [Best way to replace multiple characters in a string?](https://stackoverflow.com/questions/3411771/best-way-to-replace-multiple-characters-in-a-string) — AMC, Apr 15 '20 at 21:11

score 1 · Accepted Answer · answered Apr 15 '20 at 21:05

1

Instead of using str.replace, you can make a translation table - which is really just a dict mapping the ordinal values:

>>> string = "hello world"
>>> translation_table = str.maketrans("el", "le")
>>> translation_table
{101: 108, 108: 101}
>>> string.translate(translation_table)
'hleeo wored'
>>>

answered Apr 15 '20 at 21:05

Paul M.

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https://stackoverflow.com/questions/3411771/best-way-to-replace-multiple-characters-in-a-string – AMC Apr 15 '20 at 21:11

score 0 · Answer 2 · answered Apr 15 '20 at 21:13

0

You have xy

you replace the x by y sou you have yy

Then you replace y by x so you get xx

You ca do:

A="xy"
B=a.replace("x","z")
C=B.replace("y","x")
D=C.replace("z","y")
print(D)
#yx

answered Apr 15 '20 at 21:13

rafalou38

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score 0 · Answer 3 · answered Apr 15 '20 at 21:15

0

I am not sure if I understood your question but maybe this could work:

a = 'xy'
letters = [char for char in a]
b = ''
for l in reversed(letters):
    b += l
print(b)

And the final outcome isyx.

answered Apr 15 '20 at 21:15

csymvoul

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score 0 · Answer 4 · answered Apr 15 '20 at 21:18

According to your exemple:

c=a.replace("xy","yx")

Or for more general solution, if you are not looking for high time performance on big data volume, you can iterate:

c=[] 
for i in range(0,len(a)-1,1):
    if a[i]=="x":
        c[i] ="y"
    elif  a[i]=="y" :
        c[i] ="x"
    else:
         c[i] =a[i]

Replace multiple chars in one run

4 Answers4