matching datatype in python

Question

I'm new to python and studying deep learning using Github codes. I'm getting error TypeError: can't concat str to bytes so I tried to match the datatype.

old:

newFilename = fileGenre+"_"+str(fileID)

new:

newFilename = fileGenre+"_"+bytes(fileID)

but same error occured, so I want to know how to fix the error. fileGenre is byte varible which is from eyed3 module and fileID is int type variable.

this is part of code:

    for index,filename in enumerate(files):
       fileGenre = getGenre(rawDataPath+filename)
       genresID[fileGenre] = genresID[fileGenre] + 1 if fileGenre in genresID else 1
       fileID = genresID[fileGenre]
       newFilename = fileGenre+"_"+str(fileID) #in this line, i got error
       createSpectrogram(filename,newFilename)

Does this answer your question? [Convert bytes to a string](https://stackoverflow.com/questions/606191/convert-bytes-to-a-string) — mkrieger1, Apr 18 '20 at 09:29

Shubham Sharma · Accepted Answer · 2020-04-18T09:29:11.473

3

You can only concat str to str so when you are trying to concat str and bytes this will raise an error. You can use bytes.decode method to return a string decodes from given bytes.

Use:

newFilename = fileGenre.decode("utf-8") + "_" + str(fileID)

edited Apr 18 '20 at 09:29

answered Apr 18 '20 at 09:23

Shubham Sharma

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score 1 · Answer 2 · answered Apr 18 '20 at 09:34

1

Use:

new_filename = "{}_{}".format(fileGenre, str(file_id))

answered Apr 18 '20 at 09:34

Mostafa Taheri

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score 1 · Answer 3 · answered Apr 18 '20 at 09:35

1

you can not use string between two bytes value concatenation ("_")

so you can use this -

newFilename = str(fileGenre)+""+str(fileID) newFilename = fileGenre+""+str(bytes(fileID))

answered Apr 18 '20 at 09:35

A D

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matching datatype in python

3 Answers3