Having some trouble with try-except in python

Asked Apr 22 '20 at 22:27

Active Apr 22 '20 at 22:27

Viewed 16 times

So I wrote this function wich returns a meaning of a word that is in data.json. The problem is that the return works fine when I put some right word the first time, but after one exception it returns None.

def sig_palavra(p):
    p = p.lower()
    try:
        return str(data[p])
    except:
        print('Verifique se a palavra foi escrita corretamente')
        p = input(':')
        p = p.lower()
        sig_palavra(p)

I have this output:

> Digite a palavra pra saber seu significado: olho
> Verifique se a palavra foi escrita corretamente
>:eye
> None

But 'eye' is a valid word and it returns its meaning if I write it in the first place

asked Apr 22 '20 at 22:27

Diego Rapoport

1

You don't have a `return` statement in the `except` block. – Barmar Apr 22 '20 at 22:28
Use `return sig_palavra(p)` – Barmar Apr 22 '20 at 22:29
You shouldn't use recursion in Python as a replacement for iteration. – Barmar Apr 22 '20 at 22:30
Why shouldn't? Can you explain it better? – Diego Rapoport Apr 22 '20 at 22:35
Because iteration is generally easier to understand, the looping is obvious. – Barmar Apr 22 '20 at 22:38

Having some trouble with try-except in python

0 Answers0