I have a data frame with a name column and a ticker column, the ticker column trim with ";" if a name has more than 1 ticker. A glimpse from this data.frame below:
df.info is the name of the dataframe
Rows: 525
Columns: 2
$ name.company <chr> "521 PARTICIPAÇOES S.A. - EM LIQUIDAÇÃO EXTRAJUDICIAL", "524 PARTICIPAÇOES SA", "AAJR SECURITIZADORA DE CRÉDITO...
$ tickers <chr> NA, "QVQP3B", NA, "ADHM3", "TIET11;TIET3;TIET4", "AFLT3", NA, "ALEF3B", "RPAD3;RPAD5;RPAD6", NA, "ALSO3", "ALPA...
And I want a dataframe that has 2 columns, ticker and name.company but without the trim pattern ";".
e.g.:
name ticker
tiete tiet11
tiete tiet3
tiete tiet4
and so it goes.. I solved it using the by() function but I have no clue how to solve it using the tidyverse/purrr packages.
Solution without tidyverse
get.ticker.df <- function(df.in)
{
# Gets ticker string and organizes it in another data_frame
temp.split <- str_split(df.in$tickers, ';')[[1]]
temp.df <- tibble(name.company = df.in$name.company,
ticker = temp.split)
}
my.l <- by(data = df.info,
INDICES = df.info$name.company,
FUN = get.ticker.df)
df.tickers <- bind_rows(my.l)
I don't know the equivalent of this by() function in tidyverse.
Edit - Added initial frame and the ideal result dataframe, to make it clear.
tibble_start <- tibble( name.company = c("AES TIETE", "AMBEV"),
ticker = c("TIET11;TIET3;TIET4", "ABEV3;ABEV4"))
tibble_ideal <- tibble( name.company = c( rep("AES TIETE", 3), rep("AMBEV",2)),
ticker = c("TIET11","TIET3","TIET4","ABEV3","ABEV4"))
Thanks in advance!