I have a function returning a std::pair
, which I want to use to call an overloaded member function. I am not aware of any way to unpack a tuple in-place (which I'd prefer), so std::apply
is my best bet, I think.
This works with a combination of tuple_cat
and forward_as_tuple
when the member function is not overloaded, but otherwise, the compiler complains about an unresolved overload.
That is understandable, given that std::apply
just takes a function pointer, but I'd still like to know whether it can be made to work in a readable way.
Here's some example code:
#include <iostream>
#include <tuple>
#include <utility>
std::pair<int, int> func() { return { 0, 1 }; }
class MyClass {
public:
int memFun(int);
int memFun(int, int);
};
int MyClass::memFun(int i){ return 2*i; }
int MyClass::memFun(int a, int b){ return a+b; }
int main(){
MyClass myClass;
/* works */
std::pair pair { func() };
int number { myClass.memFun( pair.first, pair.second ) };
/* doesn't work (unresolved overload) */
int number { std::apply(
&MyClass::memFun,
std::tuple_cat( std::forward_as_tuple(myClass), func() )
) };
std::cout << number << "\n";
return 0;
}
Is there an elegant (=readable) way to do this without a temporary?
I only found this question and so far don't think it fully applies.