How can I fix this "The truth value of an array with more than one element is ambiguous. Use a.any() or a.all()"?

Asked Apr 23 '20 at 23:24

Active Apr 23 '20 at 23:24

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I wrote this for comparing two arrays and find #||≥|_| :

count = 0
for a in range(len(coeffs)):
  for b in range(len(observed_coefficient)):
    if np.abs(coeffs[a]) >= np.abs(observed_coefficient[b]):
      count += 1
print(count)

However I get this error because of the if part. How can i fix this?

asked Apr 23 '20 at 23:24

Aleyna Buse Sumer Student

Please share your dataframe and the code with expected output. – Mayank Porwal Apr 23 '20 at 23:26
try just doing: `count = sum(np.where(np.array(list(map(abs, coeffs))) >= np.array(list(map(abs, observed_coefficient))), 1, 0))` without any loops. Is that what you are looking for? – It_is_Chris Apr 23 '20 at 23:42
@Yo_Chris yep it works, thank you:) – Aleyna Buse Sumer Student Apr 24 '20 at 00:27

How can I fix this "The truth value of an array with more than one element is ambiguous. Use a.any() or a.all()"?

0 Answers0