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I am trying to understand how the one-time variable assignment needs to be done correctly in Bash. Please consider the following two examples, where I was expecting to get the same result in Bash:

unset Var 
Var=123 echo $Var
# prints nothing

I now edit the file test.sh with the following content:

#!/bin/bash
echo $Var

and execute:

unset Var 
Var=123 source test.sh
# prints 123

Can somebody please explain why there is different behavior in these two examples?

Thanks!

user9751447
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  • you need a `;` in between the variable assignment and the `echo` for it to work – Jetchisel Apr 27 '20 at 06:30
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    @Jetchisel the change you suggest produces two different statements. The question is about the one-time environment variables used with the current statement. – axiac Apr 27 '20 at 06:45

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