How to print the Correct output using " while loop "?

Question

The Expected Output is 2000 but it stops on 1980.

Note: The Execution is started from 20 and not from 0 as int i = 1

The Code:

#include <iostream>
using namespace std;
int main() {
  const int iarraysize = 100;
  int i = 1;
  int iarray[iarraysize];
  while (i < iarraysize) {
    iarray[i] = 20 * i;
    cout << iarray[i++] << "\n";
  }
}

Answer 1

Arrays start at 0, and end one before their size.

You don't need an array however.

#include <iostream>
int main()
{
    int limit = 100;
    int i = 1;
    while (i <= limit)
    {
        std::cout << (i++ * 20) << "\n";
    }
}

Answer 2

The array goes from 0 to 99, you start at 1 and it only goes to 99 (99*20=1980).

You're expecting 2000 but there's no iarray[100] (array out of bounds).

Answer 3

The last value of the variable i that is less than 100 is 99. So 20 * 99 is equal to 1990.

If you want to get 2000 then rewrite the loop like

int i = 0;
while (i < iarraysize) {
  iarray[i] = 20 * (i + 1);
  cout << iarray[i++] << "\n";
}