How to find $@º[] with regExp in JS

Asked May 01 '20 at 16:26

Active May 01 '20 at 16:26

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i need to see if a string contains at least one number, one english alfabetic character and one of those characters $ @ o [ ] I am trying this but it doesnt work.

/^(.[a-zA-Z].)(.[0-9].)(.[$@o[]].)$/.test(strPassword))

I think that the problem is with the special characters, help pls

asked May 01 '20 at 16:26

Pablo López

1

It might be simpler just to use `String.prototype.indexOf` for each character you want to find. – Dai May 01 '20 at 16:28
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I must use reg Exp, my teacher is my teacher xD – Pablo López May 01 '20 at 16:29
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https://regex101.com/ - There are several sites that can do this, but this site will help you compare your expression to your use cases. it may lend better guidance. – John Pavek May 01 '20 at 16:40
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https://stackoverflow.com/questions/19605150/regex-for-password-must-contain-at-least-eight-characters-at-least-one-number-a – Antonio Torres May 01 '20 at 16:53
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Try this. "^(?=.*[A-Za-z])(?=.*\d)(?=.*[@$!%*#?&])[A-Za-z\d@$!%*#?&]{8,}$" – Ali Hassan Ahmed Khan May 01 '20 at 16:54
In your specific case: `/^(?=.*[A-Za-z])(?=.*\d)(?=.*[$@º\[\]]).*$/` would do the job. – mateleco May 01 '20 at 19:55

How to find $@º[] with regExp in JS

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