The answer by Aasmund Eldhuset is what I was attempting to do but I was beaten to the punch. It shows a lot of research and should definitely be the accepted answer.
If you want confirmation of that answer (or just want to test it in a different implementation, such as a non-CPython one, or a later one which may use a different Unicode standard under the covers), the following short program will print out the actual characters that cause a split when using .split()
with no arguments.
It does this by constructing a string with the a
and b
characters(a) separated by the character being tested, then detecting if split
creates an array more than one element:
int_ch = 0
while True:
try:
test_str = "a" + chr(int_ch) + "b"
except Exception as e:
print(f'Stopping, {e}')
break
if len(test_str.split()) != 1:
print(f'0x{int_ch:06x} ({int_ch})')
int_ch += 1
The output (for my system) is as follows:
0x000009 (9)
0x00000a (10)
0x00000b (11)
0x00000c (12)
0x00000d (13)
0x00001c (28)
0x00001d (29)
0x00001e (30)
0x00001f (31)
0x000020 (32)
0x000085 (133)
0x0000a0 (160)
0x001680 (5760)
0x002000 (8192)
0x002001 (8193)
0x002002 (8194)
0x002003 (8195)
0x002004 (8196)
0x002005 (8197)
0x002006 (8198)
0x002007 (8199)
0x002008 (8200)
0x002009 (8201)
0x00200a (8202)
0x002028 (8232)
0x002029 (8233)
0x00202f (8239)
0x00205f (8287)
0x003000 (12288)
Stopping, chr() arg not in range(0x110000)
You can ignore the error at the end, that's just to confirm it doesn't fail until we've moved out of the valid Unicode area (code points 0x000000 - 0x10ffff
making up the seventeen planes).
(a) I'm hoping that no future version of Python ever considers a
or b
to be whitespace, as that would totally break this (and a lot of other) code.
I think the chances of that are rather slim, so it should be fine :-)