Why list printed in right order but set not?

Question

Here is my code:

my_list=[2794, 2798, 2817, 2820, 2821, 2823, 2824, 2826, 2829, 2831, 2831, 2831, 2839, 2842, 2843, 2845, 2847, 2850, 2851, 2854, 2855, 2856, 2857, 2858, 2859, 2862, 2864, 2865]

for i in my_list:
    print(i)


print("\n\n")

my_set = set(my_list)

for i in my_set:
    print(i)

output:

Question: Why list (in ascending) and set (in some other) are printed in different order?

set is unordered and un-indexed data structure. where as list is ordered data stucture. — Rima, May 05 '20 at 21:31

score 1 · Answer 1 · answered May 05 '20 at 21:33

1

That is happening because as @user2357112supportsMonica said, sets are unordered. There is an ordered set though which you can see here.

answered May 05 '20 at 21:33

xilpex

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I think it is simpler to use an `OrderedDict` or from Python 3.7 just a regular good ol' `dict` – Tomerikoo May 05 '20 at 21:37

score 0 · Answer 2 · answered May 05 '20 at 21:33

0

set is unordered and un-indexed data structure. where as list is ordered data stucture.

convert it to list

for i in list(my_set):
    print(i)

answered May 05 '20 at 21:33

Rima

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converting a `set` to a `list` and iterating on it gives the same order as iterating directly on the `set`. – Tomerikoo May 05 '20 at 21:35
Good to know. Thank you! – Rima May 05 '20 at 21:39

Why list printed in right order but set not?

2 Answers2