How can I use python to prints a series of strings mean ± std

Question

I want to print mean ± std in Python.

For instance:

 print('30', u"\u00B1", "1")

I get

 30 ± 1

But if I have sevel means and stds, for instance:

means = [20, 30 15]
stds = [7, 10, 2]

How can I get

'20 ± 7'
'30 ± 10'
'15 ± 2'

Use `zip` --> `for m, s in zip(means, stds) : print(m u"\u00B1", s)` — Rakesh, May 06 '20 at 10:43

Anwarvic · Accepted Answer · 2020-05-06T13:28:59.983

2

You can do that like so:

means = [20, 30, 15]
stds = [7, 10, 2]


for mean, std in zip(means, stds):
    x  = f"{mean} ± {std}" #x is a string
    print(x)

edited May 06 '20 at 13:28

answered May 06 '20 at 10:45

Anwarvic

how to export the result into a string? Thanks. – Wang May 06 '20 at 13:25
I've edited my answer – Anwarvic May 06 '20 at 13:29
Thanks a lot for your prompt help. I want to use x as a label in a plot. If I print x out of the for loop, I only get one element. – Wang May 06 '20 at 13:33
Then, you can save `x` in a `list` – Anwarvic May 06 '20 at 13:35
Thanks a lot. I understand it now. – Wang May 06 '20 at 13:54

score 1 · Answer 2 · answered May 06 '20 at 10:48

1

You can do

means = [20, 30, 15]
stds = [7, 10, 2]

for i in zip(means, stds):
    print(i[0], u"\u00B1", i[1])

answered May 06 '20 at 10:48

Clément

2 Answers2