Return value from function "outside"

Question

I am beginner in Laravel and php.

I have this code:

$arrayToDelete = array();
$traverse = function ($categories) use (&$traverse) {
    foreach ($categories as $category) {
        //$this->model->delete($category->id);
        echo 'Delete'.$category->category_name.' i '.$category->id.'<br/>';
        $traverse($category->children);
    }
};

dd($traverse($node));

This code return me:

Delete Mobile i 14 Delete Samsung i 15 Delete iPhone i 16 Delete Xiomi i 17

It's ok. I need add id to $arrayToDelete. How can I make it?

What have you tried so far? Where are you stuck? – Nico Haase May 06 '20 at 12:43 — Nico Haase, May 06 '20 at 12:43

score 1 · Accepted Answer · answered May 06 '20 at 12:36

You can pass more than one parameter into the USE so pass your other array, also by reference of course

$arrayToDelete = array();
$traverse = function ($categories) use(&$traverse, &$arrayToDelete) {
    foreach ($categories as $category) {
        arrayToDelete[] = $category->id;
        echo 'Delete'.$category->category_name.' i '.$category->id.'<br/>';
        $traverse($category->children);
    }
};

dd($traverse($node));

Omer YILMAZ · Answer 2 · 2020-05-06T12:44:34.823

-1

$arrayToDelete = [];
$traverse = function ($categories) use (&$traverse,&$arrayToDelete) {
    foreach ($categories as $category) {
        //$this->model->delete($category->id);
        echo 'Delete'.$category->category_name.' i '.$category->id.'<br/>';

        $arrayToDelete[] = $category->id;

        $traverse($category->children);
    }
};

dd($traverse($node));

edited May 06 '20 at 12:44

answered May 06 '20 at 12:11

Omer YILMAZ

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I make this: $arrayToDelete = []; $traverse = function ($categories) use (&$traverse) { foreach ($categories as $category) { //$this->model->delete($category->id); echo 'Delete'.$category->category_name.' i '.$category->id.'
'; $arrayToDelete[] = $category->id; $traverse($category->children); } }; $traverse($node); dd($arrayToDelete); and this is not working :( – traffske May 06 '20 at 12:16
1

Please don't write any long code as comment, this is not readable. Please update your question – Omer YILMAZ May 06 '20 at 12:24
Please use $arrayToDelete in use – Omer YILMAZ May 06 '20 at 12:29
It's not working :( – traffske May 06 '20 at 12:36
Sorry my mistake, please use $arrayToDelete in use with & – Omer YILMAZ May 06 '20 at 12:45
Is it working now? – Omer YILMAZ May 06 '20 at 12:53

Return value from function "outside"

2 Answers2