How to remove all occurrences of string in Javascript

Question

I am using JSON.stringify to convert object into string as follows:

JSON.stringify(obj).replace(/[{}]/g, '').slice(1, -1)

I am getting below output:

"null,null,"Heading":"Heading1""

I want to remove all occurrences of null from the above string, for which I am using replace

JSON.stringify(obj).replace(/[{}]/g, '').slice(1, -1).replace('null,', '')

But it only removes the first occurrence of null string

 "null,"Heading":"Heading1""

Desired output:

"Heading":"Heading1""

Why replace it in the string and not the object/array you're stringifying? — Heretic Monkey, May 06 '20 at 18:05
Does this answer your question? [How to replace all occurrences of a string?](https://stackoverflow.com/questions/1144783/how-to-replace-all-occurrences-of-a-string) — Heretic Monkey, May 07 '20 at 12:56

SMAKSS · Accepted Answer · 2020-05-06T18:23:20.050

As peeps said in comments may be the best way for this is to get rid of null element in the first place, so if you want to do that you should iterate through your object then check for null items.

For this cause this may come handy:

Object.keys(obj).forEach((key) => (obj[key] == null) && delete obj[key]);

Otherwise, you should consider using a global flag (/g) in your regex, in order to remove all null occurrence.

You can achieve this with something like this:

.replace(/null,/g, '')

score 0 · Answer 2 · answered May 06 '20 at 18:08

0

The .replace() method only replaces the first occurrence. Perform global replacement as

.replace(/null,/g, '')

Hope it helps!

answered May 06 '20 at 18:08

Deepak Terse

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How to remove all occurrences of string in Javascript

2 Answers2