How to use selenium to click on this element?

Question

How can I click on this element using selenium? I was tried using:(but was not successful)

divselected = driver.find_element_by_css_selector(div[aria-label="Add a public comment..."])

divselected.click()

I also tried

divselected = driver.find_element_by_id("contenteditable-root")
divselected.click()

The div I am trying to click:

<div id="contenteditable-root" contenteditable="true" dir="auto" class="style-scope yt-formatted-string" aria-label="Add a public comment..."></div>'

Sometimes you need to trigger more events than just click for it to work. — whackamadoodle3000, May 08 '20 at 03:12
@whackamadoodle3000 I get an error that the element cannot be found. — josephf, May 08 '20 at 03:12
@Ruyut I am trying to click on the textbox where you write your comment. — josephf, May 08 '20 at 03:14
Before clicking the element, can you add a wait for element to be clickable : https://stackoverflow.com/a/28110129/7964299 ? And also you can use xpath like `//div[contains(@aria-label, 'Add a public comment')]` — Naveen, May 08 '20 at 04:15

Amruta · Answer 1 · 2020-05-09T01:01:09.877

0

Hope this help:

divselected=driver.find_element_by_xpath("//*[contains(text(),'Add a public comment')]")

edited May 09 '20 at 01:01

answered May 08 '20 at 07:26

Amruta

I get the following: driver.find_element_by_xpath(//*[contains(text(),'Add a public comment')]) ^ SyntaxError: invalid syntax – josephf May 08 '20 at 16:29
Updated code ..forgot to put double quotes.it should work now and it will return one matching element. – Amruta May 09 '20 at 01:02

score 0 · Answer 2 · answered May 08 '20 at 16:40

0

The following code works:

divselected = driver.find_elements_by_xpath("//*[contains(text(), 'Add a public comment...')]")

divselected[0].click()

answered May 08 '20 at 16:40

josephf

How to add comment after this click. I tried sendKeys does not work. – xMayank Jun 15 '20 at 14:29

score 0 · Answer 3 · edited Feb 15 '23 at 11:46

0

try using

driver.find_element(By.ID, 'contenteditable-root').click()

or instead of ID use Class Name.

edited Feb 15 '23 at 11:46

Harsh Mangalam

answered Feb 10 '23 at 16:05

Denied Access

Your answer could be improved with additional supporting information. Please [edit] to add further details, such as citations or documentation, so that others can confirm that your answer is correct. You can find more information on how to write good answers [in the help center](/help/how-to-answer). – Community Feb 14 '23 at 18:58

3 Answers3