Initialization of array which is created before in C

Question

int a[5] = {2,4,6,8,10}; // Works

But,

int a[5];
a = {2,4,6,8,10}; //Doesn't Work

Why?

Is there any other way in which I can initialize a array in a single go which is created before.

Does this answer your question? [https://stackoverflow.com/questions/3137671/declaring-and-initializing-arrays-in-c](https://stackoverflow.com/questions/3137671/declaring-and-initializing-arrays-in-c) — Francesco, May 08 '20 at 08:20
The first is an initialization, not an assignment. The second attempts to assign an initializer to an array (as an executable assignment), which isn't supported in C. — Tom Karzes, May 08 '20 at 08:20
https://stackoverflow.com/questions/8886375/possible-to-initialize-an-array-after-the-declaration-in-c — beynDestroyer, May 08 '20 at 08:21

score 1 · Answer 1 · edited May 08 '20 at 08:43

1

I haven't tested it myself, but since C99 you should be able to use a compound literal with memcpy to copy the data into the array:

memcpy(a, (int[5]){2,4,6,8,10}, sizeof a);

edited May 08 '20 at 08:43

David Ranieri

answered May 08 '20 at 08:22

1 Answers1