Access Dict with variable name

Question

I need to create some dicts with variable names. This works perfectly with this line:

for i in range(0,5):
    locals()['dict{}'.format(i)] = {}

But how can I access on of these dictionaries?

Just don't do that. See e.g. https://stackoverflow.com/q/1373164/3001761. — jonrsharpe, May 11 '20 at 13:20
don't create names dynamically. Use dict of dicts. Or other container type. — buran, May 11 '20 at 13:20

score 0 · Answer 1 · answered May 11 '20 at 13:22

0

Nevermind, it was just as easy as this:

 i = 0
 print(locals()['dict{}'.format(i)])

answered May 11 '20 at 13:22

Matthias Pröll

1 Answers1