Regex handling "|" in Text

Question

I got the following text:

Code = ABCD123 | Points = 30
Code = ABCD333 | Points = 44

At the end, I want to removing anything except the Code, output:

ABCD123
ABCD333

I actually tried it with Code = | P.+

But I don't know how to get "|" removed. Currently, I have just ÀBCD333 | left as an example. I'm struggling there.

Have you tried ‘\|’ ? The pipe character means “or” in regex unless you escape it. — xdhmoore, May 12 '20 at 15:20
@WiktorStribiżew: I think the pipe is not the problem, OP wants to keep only the Code value. — Toto, May 12 '20 at 15:27
@WiktorStribiżew: OP's regex, (as far as I understand what he really want) is supposed to match `Code = ` OR `P.+`. — Toto, May 12 '20 at 15:31
@dnz: could you clarify what does your regex is supposed to do? — Toto, May 12 '20 at 15:40
@Toto I just want to Code e.g. ABCD123 and anything else removed — dnz, May 12 '20 at 15:47

score 0 · Accepted Answer · answered May 12 '20 at 15:19

0

Assuming the code only consists of word characters, you may use the following:

^Code = (\w+).+$

..and replace with:

\1

Demo.

If the code can be anything, you may use something like this instead:

^Code = (.+?)[ ]\|.+$

answered May 12 '20 at 15:19

ICloneable

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3
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score -1 · Answer 2 · answered May 12 '20 at 15:24

Ctrl+H
Find what: ^Code = (\w+).+
Replace with: $1
CHECK Wrap around
CHECK Regular expression
UNCHECK . matches newline
Replace all

Explanation:

^           # beginning of line
  Code =    # literally
  (\w+)     # group 1, 1 or more word character
  .+        # 1 or more any character but newline

Replacement:

$1          # content of group 1

Screenshot (before):

Screenshot (after):

Regex handling "|" in Text

2 Answers2