Regex how to match "not \1"

Question

for example: if i match "1+2+1" use "/[0-9](\+|\-)[0-9](\1)[0-9]",it works,

but now i want to match "1+2-1", but the regex "/[0-9](\+|\-)[0-9][^(\1)][0-9]/" didn't work.

so how to match the "NOT \1"?

Can you explain that further? What do you mean by "the NOT \1"? — Nico Haase, May 14 '20 at 06:53

score 1 · Accepted Answer · answered May 14 '20 at 07:05

1

You may try to use negative lookahead and don't match it if it's the same as first matched char. You can fiddle around with this expression; [0-9]([+-])[0-9](?:(?!\1)[+-])[0-9]

https://regex101.com/r/mSSSlJ/1

answered May 14 '20 at 07:05

Lostfields

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score 0 · Answer 2 · answered May 14 '20 at 08:07

0

You can use this to match both of the text:

[0-9](\+|\-)[0-9](\1)*[+-][0-9]

answered May 14 '20 at 08:07

CoderX

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Regex how to match "not \1"

2 Answers2