typescript concat warning no overloading match

Question

console.log([].concat(0, 123))

I've no clue what the error means

No overload matches this call.
  Overload 1 of 2, '(...items: ConcatArray<never>[]): never[]', gave the following error.
    Argument of type '0' is not assignable to parameter of type 'ConcatArray<never>'.
  Overload 2 of 2, '(...items: ConcatArray<never>[]): never[]', gave the following error.
    Argument of type '0' is not assignable to parameter of type 'ConcatArray<never>'.ts(2769)

I assign to a variable and declare any type I still see the error.

This `console.log(([] as number[]).concat(0, 123))` works. Check: https://stackoverflow.com/a/54117175 for further information. — Yoshi, May 14 '20 at 08:21

DevLoverUmar · Accepted Answer · 2020-05-14T08:26:02.130

1

Try this:

console.log(([] as any[]).concat(0, 123));

For more info, check this github issue

edited May 14 '20 at 08:26

answered May 14 '20 at 08:16

DevLoverUmar

11,809
11
68
98

typescript concat warning no overloading match

1 Answers1