C# Do not define variable for not used out parameter

Question

Possible Duplicate:
Is there a way to omit out parameter?

Instead of:

SomeType param3;
SomeMethodCall(param1, param2, out param3);

I want not to define param3 in the case I don't need its value.

Is there any way to achieve this?

Write a wrapper (overload) for the `SomeMethodCall` function without the out parameter. — CaffGeek, May 30 '11 at 17:43

score 1 · Answer 1 · answered May 30 '11 at 17:43

1

No, there is no way of doing that in C#.

answered May 30 '11 at 17:43

Pablo Santa Cruz

score 1 · Answer 2 · answered May 30 '11 at 17:44

1

If SomeMethodCall is something you defined yourself then you can overload the method. If it's not then you can't.

answered May 30 '11 at 17:44

Jan-Peter Vos

1

Well I guess you could with an extension method or something. – BoltClock May 30 '11 at 17:45
@BoltClock Nice one :) Forgot about that one. – Jan-Peter Vos May 30 '11 at 17:57

score 0 · Answer 3 · answered May 30 '11 at 17:44

0

No, you'll have to actually create a variable of the correct type if you want to use a function that takes an out parameter.

answered May 30 '11 at 17:44

Seth Carnegie

3 Answers3