Python function in an if-statement

Question

I have a function which returns true/false. Now I tried to use in a condicional, like this:

isOdd = lambda n: True if n%2 != 0 else False

if !isOdd(2): 
  print('Yey')

but I got SyntaxError: invalid syntax

how could I use ! in a function like this? it looks like this only works if:

if isOdd(2) == False: 
  print('Yey')

Note that `True if n%2 != 0 else False` can be written as `n%2 != 0`. — Fred Larson, May 14 '20 at 19:48

score 2 · Answer 1 · answered May 14 '20 at 19:46

2

I don't believe Python uses ! for negation like C does. Try

if not isOdd(2):

answered May 14 '20 at 19:46

Daniel Walker

1 Answers1