I'm trying to download a video from a website, they use a company called ooyala to host their videos, so i think you can't find it through searching the elements on the page. I'm trying to use selenium to click the play button, and get the url of the video through the network tab. This is my code so far
import time
from selenium import webdriver
from selenium.webdriver.chrome.options import Options
from selenium.webdriver.common.desired_capabilities import DesiredCapabilities
def get_link():
chrome_options = Options()
chrome_options.add_experimental_option("detach", True)
caps = DesiredCapabilities.CHROME
caps['loggingPrefs'] = {'browser': 'ALL'}
url_main = r'https://www.channelnewsasia.com/news/video-on-demand/japanhour'
path = r'C:\Users\User\Downloads\Internet download\chromedriver_win32\chromedriver.exe'
driver = webdriver.Chrome(path, chrome_options=chrome_options,desired_capabilities=caps)
driver.get(url_main)
time.sleep(10)
link = driver.find_element_by_class_name('video__custom-duration')
link.click()
while True:
for entry in driver.get_log('browser'):
print(entry)
The clicking works but the loggingPrefs doesn't, I think it's returning error messages. I've tried to look for the documentation but i can't find what other types of args goes into the DesiredCapabilities dictionary. Can anyone give me some assistance?
TLDR:
How do I read from the network tab in chrome?
Additional info.
The url i'm using is georestricted to singapore, so here's another random video for anyone helping me, not using ooyala though. https://www.rollingstone.com/music/music-news/norwegian-dj-cashmere-cat-goes-spartan-on-with-me-premiere-71196/
If you accessing the original url with a vpn, heres the link i am trying to find automatically https://mediacorp-videosaz.akamaized.net/c642f1d9-bfcd-46fe-8304-b4bf5c236d1e/BsY3hkajE6J_wuuYqP4M6HATpdD8CwlF.ism/QualityLevels(1984000)/Manifest(format=m3u8-aapl)