list1 is a list here in python and i is some constant like 7(integer).
Look at the snippet of code below :-
for j in range(i, len(list1)):
if list1[j][0] == 'Ġ' or '.' or '!' or '?' or ',':
#do something
When I execute the above code only 'Ġ' is considered for checking whether the list1 ith string's first character is 'Ġ' or not and the rest '.','!','?'and ',' are ignored.
I also thought of using the startswith() fucntion like this :-
for j in range(i, len(list1)):
if list1[j].startswith([Ġ!?.,]):
#do something
But then the above code also wasn't working properly, because I realized that startswith() function doesn't accept regular expression. Also, it accepts only one character so that implies that I can't add parameters like this :-
if list1[j].startswith('Ġ' or '.' or '!' or '?' or ','):
Does anybody know of what could be done here? Please help. I want to check whether the first character of the string belongs to any of these character - 'Ġ', '.', '!', '?', ','
