Regex: Basic pattern for date format (dd.mm.yyyy) not working

Question

I am new to Regex and am trying to create a basic date pattern for a text input field in HTML.

For now I only want to consider the following rules:

Allowed examples:

I tried the following but this does not work for me.
Can someone tell me what I am missing here ?

My Regex pattern:

pattern="[01-31].[01-12].[1961-2100]"

Update:

pattern in my case is the HTML pattern attribute not a variable in JS.

Many thanks in advance,
Tom

That's not how [Character Classes](https://www.regular-expressions.info/charclass.html) work. — 41686d6564 stands w. Palestine, May 17 '20 at 05:43
@AhmedAbdelhameed: Yes, that helps regarding the number groups. Thank a lot. How do I check that only dots / periods are allowed for the separator ? — keewee279, May 17 '20 at 05:49

score 1 · Answer 1 · answered May 17 '20 at 05:50

1

try this :

pattern = "(0[1-9]|1[0-9]|2[0-9]|3[0-1])\.(0[1-9]|1[0-2])\.(\d){4}";

answered May 17 '20 at 05:50

Escanor

Thanks a lot. This helps but it's missing the range for the last number group and it's not working for me. Note: pattern in my case is the HTML pattern attribute not a variable in JS. – keewee279 May 17 '20 at 06:03
1

im sorry! so try this instead of (\d) : (19[6-9][0-9]|20[0-9]{2}|2100) – Escanor May 17 '20 at 06:21

score 1 · Answer 2 · edited Jun 20 '20 at 09:12

1

Try with this regex: (0[1-9]|[12]\d|3[0-1])[\./]([0[1-9]|1[0-2])[\./](196[1-9]|19[7-9]\d|20\d\d|2100)

edited Jun 20 '20 at 09:12

Community

answered May 17 '20 at 05:56

GolamMazid Sajib

Thanks a lot ! Looks like it's missing the years from 1980 to 1999 and it's not working for me. – keewee279 May 17 '20 at 05:59
1

@keewee279 check demo it will match 1980 to 1999 – GolamMazid Sajib May 17 '20 at 06:58
Thanks again. Unfortunately, it doesn't work for me this way. It only works if I skip the leading zeros on the first number group. – keewee279 May 17 '20 at 09:53
I found a way that works for me and posted it below. – keewee279 May 17 '20 at 10:34
@keewee279 i gave prefix 0 optional. now edited – GolamMazid Sajib May 17 '20 at 10:37

keewee279 · Answer 3 · 2020-05-17T10:34:58.967

0

I found a solution that works for me:

pattern="(0[1-9]|[12][0-9]|[3][0-1])[\.]0*([1-9]|1[0-2])[\.](196[1-9]|19[7-9][0-9]|20[0-8][0-9]|209[0-9])"

Thanks,
Tom

edited May 17 '20 at 10:34

answered May 17 '20 at 09:58

keewee279

Why so complex?: 20[0-8][0-9]|209[0-9] rather than 2\d{3} – TonyR May 17 '20 at 14:39

3 Answers3