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recently started to learn python and there was a problem .... I need to unzip the rar file, which is password protected, but the password is written in the file name, which is in the archive. And so ~ 300 times. How, with what and where can this be implemented? For example, there is an archive 383442389.rar, it has two files, pass-1337643656.data (the name contains the archive password) and the following archive)

Igor Bezrodnyy
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1 Answers1

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I'm not sure of all the context of your question, but I will try to answer you.

  1. You said that you need to unzip a file .rar, but that is not possible, if the file is .rar you need to unrar

  2. If you need just to unzip a .zip

something like that should work

from zipfile import ZipFile
with ZipFile('test1.zip', 'r') as myzip:
    myzip.extractall(pwd='<password>')
  1. In the case of .rar

pip install rarfile (installed only in python 3)

from rarfile import RarFile
with RarFile('test2.rar', 'r') as myrar:
    myrar.extractall(pwd='<password>')
  1. you mention that the password comes in the .rar like a name of file
    • pass-1337643656.data
    • you can list the names of the files using

RarFile.namelist() Return a list of archive members by name.

So you can extract the password using split 

s = 'pass-1337643656.data'
s.split('-')[1].split('.')[0]
print(s)

'1337643656'

you can use also a regular expression to extract that

Conclusion.

A complete solution using .rar could be

from rarfile import RarFile
with RarFile('test2.rar', 'r') as myrar:
    file_names = myrar.namelist()
    pass_file = list(filter(lambda k: 'pass' in k, l))[0]
    pass = pass_file.split('-')[1].split('.')[0]
    myrar.extractall(pwd=pass)

Reference.

kolya5544
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Cyberguille
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  • Hello! Yes, I was a little mistaken with the words, I need a case with .rar. In this case, I still need to do the code execution up to 300 times (so that only the final result appears in C: \ Users \ Usero \ Desktop). Still, how can I specify the path to test2.rar? Here is an example of such a rar file, you can look at the link: https://myfile.is/h0325b00o8/Enclosed_rar (Also, when compiling, an error occurs: Syntax error in C: \ Users \ Usero \ script.py   File "C: \ Users \ script.py", line 5      pass = pass_file..split ('-') [1] .split ('.') [0]           ^  SyntaxError: invalid syntax – Igor Bezrodnyy May 17 '20 at 22:39
  • @IgorBezrodnyy I set the path relative to the current folder where I have my script in this line with ```RarFile('test2.rar', 'r') as myrar:``, I you read the referece that I let you regarding to rarfile you can see the specification of the constructor of the object ```RarFile```, as you can see here ``` rarfile.RarFile(file[, mode='r'])``` where file should be a path to a file – Cyberguille May 18 '20 at 02:15
  • Regarding to the syntax error in the message you can see there are 2 unnecessary points ```pass_file..split ('-') [1] .split ('.') [0]```, maybe an error of copy and paste , because of in the answer I didn't see that error, should be ```pass_file.split ('-') [1] .split ('.') [0]``` – Cyberguille May 18 '20 at 02:20
  • @IgorBezrodnyy The idea of stackoverflow isn't to solve all your problem, just clarify something more specifically, that maybe you don't know or a weird I know that you are a new user of stackoverflow, I think that you need to double check this page https://stackoverflow.com/tour – Cyberguille May 18 '20 at 02:27